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11x^2-425=0
a = 11; b = 0; c = -425;
Δ = b2-4ac
Δ = 02-4·11·(-425)
Δ = 18700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18700}=\sqrt{100*187}=\sqrt{100}*\sqrt{187}=10\sqrt{187}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{187}}{2*11}=\frac{0-10\sqrt{187}}{22} =-\frac{10\sqrt{187}}{22} =-\frac{5\sqrt{187}}{11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{187}}{2*11}=\frac{0+10\sqrt{187}}{22} =\frac{10\sqrt{187}}{22} =\frac{5\sqrt{187}}{11} $
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